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Rhys Sage
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 Posted: Tue Jan 13, 2004 7:46 pm Post subject: How much one forgets |
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A friend of mine was doing maths as part of her introductory course in
college. We were sitting, stumped over a simple question. I remember passing
much more advanced maths exams on my degree.
Any solutions for: x + 4 = 2x -7?
--
Yours
Rhys
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Sadly,
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Jeff Overcash (TeamB)
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| Posted: Tue Jan 13, 2004 7:50 pm Post subject: Re: How much one forgets |
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Rhys Sage wrote:
| Quote: |
A friend of mine was doing maths as part of her introductory course in
college. We were sitting, stumped over a simple question. I remember passing
much more advanced maths exams on my degree.
Any solutions for: x + 4 = 2x -7?
|
x + 4 = 2x - 7
4 + 7 = 2x - x
11 = x
--
Jeff Overcash (TeamB)
(Please do not email me directly unless asked. Thank You)
If there is somebody up there could they throw me down a line. Just a
little helping hand just a little understanding. Just some answers to the
questions that surround me now. If there's somebody up there could
they throw me down a line. (Fish)
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Duane Hebert
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| Posted: Tue Jan 13, 2004 7:56 pm Post subject: Re: How much one forgets |
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"Rhys Sage" <abuse (AT) 127 (DOT) 0.0.1> wrote
| Quote: |
A friend of mine was doing maths as part of her introductory course in
college. We were sitting, stumped over a simple question. I remember passing
much more advanced maths exams on my degree.
Any solutions for: x + 4 = 2x -7?
x + 4 = 2x - 7 |
x = 2x - 11
0 = x - 11
11 = x
11 + 4 = 22 - 7
15 = 15
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R.F. Pels
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| Posted: Tue Jan 13, 2004 9:49 pm Post subject: Re: How much one forgets |
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Rhys Sage wrote:
| Quote: |
A friend of mine was doing maths as part of her introductory course in
college. We were sitting, stumped over a simple question. I remember
passing much more advanced maths exams on my degree.
Any solutions for: x + 4 = 2x -7?
|
Yes. There always is a solution for a linear equation. Watch:
x + 4 = 2x - 7
subtract 4 from both ends
x = 2x - 11
subtract 2x from both ends
-x = -11
multiply by -1 on both ends
x = 11
Next, substitute x with 11 in the original:
11 + 4 = 22 - 7
add both terms on both sides
15 = 15
correct solution.
Keep in mind that with these kind of equations you have to perform the same
operation on both sides until the right side equals a constant. Then use
that constant to substitute x in the original equation and normalize. Mind
you, with quadratic equations there is a maximum of two solutions, etc...
--
Ruurd
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Igor Baranovskyy
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| Posted: Wed Jan 14, 2004 9:14 pm Post subject: Re: How much one forgets |
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Yea. A couple bottles of beer and several hours to sleep. :)
"Rhys Sage" <abuse (AT) 127 (DOT) 0.0.1> wrote
| Quote: |
A friend of mine was doing maths as part of her introductory course in
college. We were sitting, stumped over a simple question. I remember
passing
much more advanced maths exams on my degree.
Any solutions for: x + 4 = 2x -7?
--
Yours
Rhys
Join the anti-spam project:
http://groups.yahoo.com/group/Anti-Spam-Development/
or view my website:
http://www.sageworld.freeserve.co.uk
"Software is always designed to be operated by the average 8 year old.
Sadly,
most users never aspire to that level of intelligence."
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