BorlandTalk.com Borland discussion newsgroups   Archives   FAQ   Search   Memberlist   Usergroups   Register   Profile   Log in to check your private messages   Log in  Accessing Vista Functions in C          BorlandTalk.com Forum Index -> C++ Builder (Command Line Tools) View previous topic :: View next topic   Author Message Jim W. Guest Posted: Thu Oct 26, 2006 6:18 am    Post subject: Accessing Vista Functions in C I'm using the Borland Command Line Compiler and working in straight C. The system is Windows Vista RC1. I'm trying to implement an interface to the new Vista UI's that are not available in XP. So here is what I have so far. I have the manifest setup to bring in version 6 of the comctl32.dll. I defined a function as: int* (*TaskDialogProc)(HWND hwnd,HINSTANCE hinst,char *s1,char *s2, char *s3,int i, int j, int *k); <snip> int res = 0; HANDLE DllHandle; <snip> DllHandle = LoadLibrary("comctl32.dll"); if (DllHandle >= 32) { TaskDialogProc = GetProcAddress(DllHandle,"TaskDialog"); iret = (*TaskDialogProc)(NULL, NULL, L"Title", L"String1",L"String2", 1, 102, &res); } This displays the Vista TaskDialog with the strings and the OK button and the Question Mark icon as it should -- but the program simply "goes away" after I hit the OK button on the TaskDialog. My best guess is the stack is getting messed up. I put a MessageBox after the call to check the return value but it doesn't get to it. Any help would be appreciated. JimW Back to top Ed Mulroy Guest Posted: Sat Oct 28, 2006 4:31 am    Post subject: Re: Accessing Vista Functions in C Windows does not use C calling convention except for rare functions such as wsprintf. Most of the functions use __stdcall calling conventions. WINAPI is a macro in the Windows headers which translates to __stdcall. Using the wrong calling convention will mess up the stack and probably generate symptoms such as you describe. Try adding WINAPI. I also wonder about the extra asterisk used here: Quote: int* (*TaskDialogProc)(HWND hwnd,HINSTANCE hinst, char *s1,char *s2, char *s3,int i, int j, int *k); Does it return a pointer to int or an int? Your code is as if it is an int and not an int*. It looks as if the asterisk between the 'int' and the opening parentheses should be removed. Maybe this will work better: int (* WINAPI TaskDialogProc)(HWND hwnd,HINSTANCE hinst, char *s1,char *s2, char *s3,int i, int j, int *k); .. Ed Quote: Jim W wrote in message news:J1U%g.18656$A27.18410@trnddc08... I'm using the Borland Command Line Compiler and working in straight C. The system is Windows Vista RC1. I'm trying to implement an interface to the new Vista UI's that are not available in XP. So here is what I have so far. I have the manifest setup to bring in version 6 of the comctl32.dll. I defined a function as: int* (*TaskDialogProc)(HWND hwnd,HINSTANCE hinst, char *s1,char *s2, char *s3,int i, int j, int *k); snip int res = 0; HANDLE DllHandle; snip DllHandle = LoadLibrary("comctl32.dll"); if (DllHandle >= 32) { TaskDialogProc = GetProcAddress(DllHandle,"TaskDialog"); iret = (*TaskDialogProc)(NULL, NULL, L"Title", L"String1", L"String2", 1, 102, &res); } This displays the Vista TaskDialog with the strings and the OK button and the Question Mark icon as it should -- but the program simply "goes away" after I hit the OK button on the TaskDialog. My best guess is the stack is getting messed up. I put a MessageBox after the call to check the return value but it doesn't get to it. Any help would be appreciated. Back to top Jim W. Guest Posted: Sat Oct 28, 2006 6:41 am    Post subject: Re: Accessing Vista Functions in C "Ed Mulroy" <dont_email_me (AT) bitbuc (DOT) ket> wrote in message news:454296df$1 (AT) newsgroups (DOT) borland.com... Quote: Windows does not use C calling convention except for rare functions such as wsprintf. Most of the functions use __stdcall calling conventions. WINAPI is a macro in the Windows headers which translates to __stdcall. Using the wrong calling convention will mess up the stack and probably generate symptoms such as you describe. Try adding WINAPI. I also wonder about the extra asterisk used here: int* (*TaskDialogProc)(HWND hwnd,HINSTANCE hinst, char *s1,char *s2, char *s3,int i, int j, int *k); Does it return a pointer to int or an int? Your code is as if it is an int and not an int*. It looks as if the asterisk between the 'int' and the opening parentheses should be removed. Maybe this will work better: int (* WINAPI TaskDialogProc)(HWND hwnd,HINSTANCE hinst, char *s1,char *s2, char *s3,int i, int j, int *k); Ed, Thanks. I was just about to answer my own post with the solution. The Win32 group offered it up. int* (__stdcall *TaskDialogProc)(HWND hwnd, HINSTANCE hinst, char *a, char*b, char *c, int i, int d, int *k); It working just fine now. JimW Back to top Ed Mulroy Guest Posted: Sat Oct 28, 2006 6:19 pm    Post subject: Re: Accessing Vista Functions in C That still prototypes it as returning a pointer to int and you are then assigning the return value to an int. Sure you can "get away with it" until such time as you don't and then it wil be a debug session to find out what is wrong. If it returns an int, prototype it as returning an int, not a pointer to int. .. Ed Quote: Jim W wrote in message news:4zy0h.101$CT5.55@trnddc02... Thanks. I was just about to answer my own post with the solution. The Win32 group offered it up. int* (__stdcall *TaskDialogProc)(HWND hwnd, HINSTANCE hinst, char *a, char*b, char *c, int i, int d, int *k); It working just fine now. Back to top Jim W. Guest Posted: Sat Oct 28, 2006 8:20 pm    Post subject: Re: Accessing Vista Functions in C "Ed Mulroy" <dont_email_me (AT) bitbuc (DOT) ket> wrote in message news:454359ba (AT) newsgroups (DOT) borland.com... Quote: That still prototypes it as returning a pointer to int and you are then assigning the return value to an int. Sure you can "get away with it" until such time as you don't and then it wil be a debug session to find out what is wrong. If it returns an int, prototype it as returning an int, not a pointer to int. . Ed Thanks Ed, I was so excited about getting a TaskDialog up your post didn't register. Thanks for being persistent. 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