BorlandTalk.com

Chris · Guest

I have an activeX and one of the functions of it is to get a
current Image from a camera.

-------------------------------------------
VARIANT buffer;
long size;

GetCurrentImage( 1, &buffer, &size);
//(0 for jpg:1 for bmp, buffer where image is returned, buffer size)

SAFEARRAY * psa;

psa = buffer.parray;

void * buff2 = psa;
int sz = size;

TMemoryStream* fstream = new TMemoryStream;

fstream->Size = sz;
fstream->Position = 0;
fstream->Write(buff2,sz);
fstream->Position = 0;

fstream->SaveToFile("test.txt");
------------------------------------------------------

I can recieve the buffer from the activeX using the
type 'VARIANT'. However, It seems as if it needs to be
converted in order for me to actually store it as a Bitmap or
JPEG.

Do you have any suggestions on how I can get the correct format from the Variant?

Thanks,

Chris

chris · Guest

I forgot to mention that the buffer variable that I was
recieving was listed as type 'tagVariant *' in the
GetCurrentImage function.

GetCurrentImage(int,tagVariant *, long *);

Remy Lebeau (TeamB) · Guest

"Chris" <nospam (AT) workhard (DOT) com> wrote in message
news:4630b65a$1 (AT) newsgroups (DOT) borland.com...

Chris · Guest

I am going to do a lot more processing to the image after I can receive it. The code I sent was temporary test code that I create in a seperate application until I can learn all the functionality of what I want to do.

I was only semi-familiar with SafeArrays... so what you sent should help.

Thanks again,

Chris